→ O produto entre as raízes será -15.
Vamos resolver aplicando a fórmula de Bhaskara:
[tex]\huge \text {$ \sf x = \dfrac {-b \pm \sqrt{b^2 - 4ac} }{2a} $}\\\\\\\huge \text {$ \sf x = \dfrac {-2 \pm \sqrt{2^2 - 4.-1.15} }{-2} $}\\\\\huge \text {$ \sf x = \dfrac {-2 \pm \sqrt{64} }{-2} $}\\\\\huge \text {$ \sf x_1 = \dfrac {-2 - 8 }{-2} = 5 $}\\\\\huge \text {$ \sf x_2 = \dfrac {-2 + 8 }{-2} = -3 $}[/tex]
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