[tex]\cfrac{(n-6)!}{(n-5)!} = \cfrac{1}{32} \\\\\cfrac{(n-6)!}{(n-5) \cdot (n-6)!} = \cfrac{1}{32}\\\\\cfrac{1}{n-5} = \cfrac{1}{32}\\\\n - 5 = 32\\n = 37[/tex]
Resposta:
Explicação passo a passo:
(n-6)!/ (n-5).(n-6)!= 1/32
(n-6)!/(n-6)! . 1/(n-5) = 1/32
"32= n-5"
"32+5= n"
"n=37"
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