Se y = [(-5/3)^2 : (3/5)^-2].(0,01)^-3, então log100 y vale:
a)5
b)2
c)7
d)3
e)6​


Resposta :

Letra D.

y = [(- 5/3)² : (3/5)⁻²] . (0,01)⁻³

y = [(5/3)² : (5/3)²] . (1/100)⁻³

y = 1 . 100³

y = 100³

log₁₀₀(100³) = 3log₁₀₀(100) = 3 . 1 = 3