Resposta :
[tex] > \: resolucao \\ \\ \geqslant \: progressao \: \: aritmetica \\ \\ a1 = 5 \\ r = 3 \\ n = 10 \\ \\ > \: o \: decimo \: termo \: da \: pa \\ \\ an = a1 + (n - 1)r \\ an = 5 + (10 - 1)3 \\ an = 5 + 9 \times 3 \\ an = 5 + 27 \\ an = 32 \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \geqslant \geqslant \geqslant [/tex]
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Resposta:
[tex]\textsf{Segue a resposta abaixo}[/tex]
Explicação passo-a-passo:
[tex] \mathsf{ a_n=a_1+(n-1)\cdot r } [/tex]
[tex] \mathsf{a_{10}=5+(10-1)\cdot3 } [/tex]
[tex] \mathsf{a_{10}=5+9\cdot3 } [/tex]
[tex] \mathsf{ a_{10}=5+ 27} [/tex]
[tex]\boxed{\boxed{ \mathsf{ a_{10}= 32}}} [/tex]