Resposta :
[tex] > \: resolucao \\ \\ \geqslant \: perimetro \: \: do \: \: retangulo \\ \\ \\ p = 2(c + l) \\ 100 = 2(10 + l + l) \\ 100 = 2(10 + 2l) \\ 100 = 20 + 4l \\ 4l = 100 - 20 \\ 4l = 80 \\ l = \frac{80}{4} \\ l = 20 \\ \\ \\ c = 10 + l \\ c = 10 + 20 \\ c = 30 \\ \\ \\ resposta \: \: > \: \: 20cm \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \geqslant [/tex]
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Resposta: 20cm
Explicação passo a passo:
x+x+x+10+x+10=100
4x=100-10-10
4x=80
x=80/4
x=20