Resposta :
[tex] > resolucao \\ \\ \geqslant progressao \: geometrica \\ \\ an = 131072 \\ q = 2 \\ n = 15 \\ \\ \\ an = a1 \times q {}^{n - 1} \\ 131072 = a1 \times 2 {}^{15 - 1} \\ 131072 = a1 \times 2 {}^{14} \\ 131072 = a1 \times 16384 \\ a1 = \frac{131072}{16384} \\ a1 = 8 \\ \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \geqslant \leqslant \geqslant \geqslant [/tex]
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