Sendo A1 = 3q = A2/A1 = 6/3 = 2
A formula é a seguinte [tex]An = A1 .qx^{n-1} \\\\A8 = 3.2^{7} \\A8 = 3.128\\A8 = 384[/tex]
[tex] > resolucao \\ \\ \geqslant progressao \: \: geometrica \\ \\ q = \frac{a2}{a1} \\ q = \frac{6}{3} \\ q = 2 \\ \\ \\ > \: o \: oitavo \: termo \: da \: pg \\ \\ an = a1 \times q {}^{n - 1} \\ an = 3 \times 2 {}^{8 - 1} \\ an = 3 \times 2 {}^{7} \\ an = 3 \times 128 \\ an = 384 \\ \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \geqslant [/tex]
