Resposta :
[tex] > resolucao \\ \\ \geqslant equacao \: \: do \: \: 2 \: \: grau \\ \\ \\ {x}^{2} + x = 12 \\ {x}^{2} + x - 12 = 0 \\ \\ delta = 1 {}^{2} + 4.1.( - 12) \\ delta = 1 + 48 \\ delta = 49 \\ delta = \sqrt{49} \\ delta = + - 7 \\ \\ x1 = \frac{ - 1 + 7}{2} \\ x1 = \frac{6}{2} \\ x1 = 3 \\ \\ x2 = \frac{ - 1 - 7}{2} \\ x2 = \frac{ - 8}{2} \\ x2 = - 4 \\ \\ \\ s \: > \: ( \: \: 3 \: \: \: . \: \: \: - 4 \: \: ) \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \leqslant \geqslant \geqslant \geqslant [/tex]
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