Resposta :
[tex] > resolucao \\ \\ \geqslant progressao \: \: geometrica \\ \\ a10 = 243 \\ q = 3 \\ \\ \\ an = a1 \times q {}^{n - 1} \\ 243 = a1 \times 3 {}^{10 - 1} \\ 243 = a1 \times 3 {}^{9} \\ 243 = a1 \times 19683 \\ a1 = \frac{243}{19683} \\ a1 = \frac{1}{81} \\ \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \leqslant \geqslant \geqslant \geqslant \geqslant [/tex]
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