Resposta :
Resposta:
Q₁ = Q₂ = 2,98.10⁻⁴ C
Explicação:
d = 2 m
F = 200 N
Q₁ = Q
Q₂ = Q
[tex]F = k\frac{Q_{1} .Q_{2} }{d^2}\\\\200= 9.10^9\frac{Q *Q}{2^2}\\\\200 = \frac{9.10^9.Q^2}{4} \\\\9.10^9.Q^2=4*200\\\\9.10^9.Q^2=800\\\\Q^2 = \frac{800}{9.10^9} \\\\Q^2=\frac{88,9}{10^9} \\\\Q^2=88,9.10^{-9} \\\\Q^2=8,89.10^{-8}\\\\Q = \sqrt{8,89.10^{-8}} \\\\Q = 2,98.10^{-4} C[/tex]