85)
[tex]\sqrt[8]{\frac{3^{97}+3^{99}}{30}} =\frac{\sqrt[8]{3^{97}+3^{99}} }{\sqrt[8]{30} } =\frac{\sqrt[8]{3^{97}+3^{97}*3^{2}} }{\sqrt[8]{30} } =\frac{\sqrt[8]{3^{97}*(1+3^{2})} }{\sqrt[8]{30} }[/tex]=
[tex]\frac{\sqrt[8]{3^{97}}*\sqrt[8]{1+3^{2}} }{\sqrt[8]{30} } = \frac{3^{12}* \sqrt[8]{3}*\sqrt[8]{10} }{\sqrt[8]{30} } =\frac{3^{12}*\sqrt[8]{30} }{\sqrt[8]{30} } =3^{12}[/tex]
Alternativa D
86)
[tex]\sqrt{\frac{4}{3}}-\sqrt{\frac{3}{4}} = \frac{\sqrt{4}}{\sqrt{3}}-\frac{\sqrt{3}}{\sqrt{4}} = \frac{2}{\sqrt{3}}-\frac{\sqrt{3}}{2} =\\\\\frac{4-3}{2\sqrt{3}} =\frac{1}{2\sqrt{3}} = \frac{\sqrt{3}}{2*3} = \frac{\sqrt{3}}{6}[/tex]
Alternativa A
espero q compreenda o desenvolvimento.
Boa noite =)
[tex]\frak{Scorpionatico}[/tex]
