Resposta :
[tex] > resolucao \\ \\ \\ \geqslant progressao \: geometrica \\ \\ \\ q = \frac{a2}{a1} \\ \\ q = \frac{6}{3} \\ \\ q = 2 \\ \\ \\ \\ \geqslant \: o \: oitavo \: termo \: da \: pg \: \\ \\ \\ an = a1 \times q {}^{n - 1} \\ \\ an = 3 \times 2 {}^{8 - 1} \\ \\ an = 3 \times 2 {}^{7} \\ \\ an = 3 \times 128 \\ \\ an = 384 \\ \\ \\ \\ = = = = = = = = [/tex]
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