Calcule a distância de:A(0,2), B(3,6)

Resposta :

[tex] \mathsf{d_{AB}=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2} }[/tex]

[tex] \mathsf{d_{AB}=\sqrt{(3-0)^2+(6-2)^2} }[/tex]

[tex] \mathsf{d_{AB}=\sqrt{(3)^2+(4)^2} }[/tex]

[tex] \mathsf{d_{AB}=\sqrt{9+16} }[/tex]

[tex] \mathsf{d_{AB}=\sqrt{25} }[/tex]

[tex] \boxed{\boxed{\mathsf{ d_{AB}=5}}}[/tex]