Sendo a fórmula do pH dada por:
[tex]\Large\displaystyle\text{$\begin{gathered} \sf pH=-\log\left[H^+\right]\end{gathered}$}[/tex]
Temos que se o pH for igual a 3,76 o H será igual a:
[tex]\Large\displaystyle\text{$\begin{gathered} \sf \log\left[H^+\right]=-3,76\end{gathered}$}[/tex]
[tex]\Large\displaystyle\text{$\begin{gathered} \sf H^+=10^{-3,76}\end{gathered}$}[/tex]
[tex]\Large\displaystyle\text{$\begin{gathered} \sf H^+\right=\frac{1}{10^{3,76}} \end{gathered}$}[/tex]
[tex]\Large\displaystyle\text{$\begin{gathered} \sf H^+\right\approx 0.00017\end{gathered}$}[/tex]
Veja mais sobre:
- brainly.com.br/tarefa/49457542
