sendo
[tex] g(x)=\frac{3}{5} x + 7 \: diga[/tex]
a. g(-7)
b. g(0)
C. g(-2)
[tex] d (\: \frac{5}{3} )[/tex]


Resposta :

a. g(-7) = 3/5•(-7) + 7 = -21/5 + 7 = (-21 + 35)/5 = 14/5

b. g(0) = 3/5•0 + 7 = 0 + 7 = 7

c. g(-2) = 3/5•(-2) + 7 = -6/5 + 7 = (-6 + 35)/5 = 31/5

d. g(5/3) = 3/5•5/3 + 7 = 1 + 7 = 8