MANDIINHA1334GO
Respondido

IDEIA ALGÉBRICA!!!!!!!!!! ME AJUDEMMM PRFV (CONTAS ARMADAS!!!)

A)23+___=50

B)82-___=50

C)___-37=50

D)2+6.___=50

E)___-20:2=50

F) (___-5).2=50

G)2.___.5=50

H)90:___+41=50

PRFVV RESPOSTA CERTA​

Resposta :

Resposta:

A)27  

B)32  

C)87  

D)8  

E)60  

F)30  

G)5  

H)10

Explicação passo a passo:

[tex]A) 23 + X = 50\\X = 50 - 23\\X = 27\\\\B) 82 - X = 50\\-X = 50 - 82\\-X = -32\\-X * -1 = -32 * -1\\X = 32\\\\C) X - 37 = 50\\X = 50 + 37\\X = 87\\\\D) 2 + 6X = 50;\\6X = 50 - 2\\X = \frac{48}{6}\\X = 8\\\\E) X - \frac{20}{2} = 50\\X - 10 = 50\\X = 50 + 10\\X = 60\\\\F) (X - 5) * 2 = 50\\X - 5 = \frac{50}{2}\\X - 5 = 25\\X = 25 + 5\\X = 30\\\\G) 2 * X * 5 = 50\\10X = 50\\X = \frac{50}{10}\\X = 5\\\\H) \frac{90}{X} + 41 = 50\\\frac{90}{X} = 50 - 41\\\frac{90}{X} = 9\\90=9X[/tex]

[tex]\frac{90}{9}=X\\X = 10[/tex]

DSANTOS9002GO

basta realizar a operação inversa o que está se pedindo

a) 50 - 23 = a 27

b) 82 - 50 = 32

c) 50 + 37 = 87

d) 2 + 6 . 8 = 50

e)60 - ( 20/2)=50

f) (30 - 5) . 2 =50

g) 2 . 5 . 5 =50

h) ( 90/9) + 41 = 50

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