Resposta :
Resposta:
[tex] \frac{(3x + 5)}{4} - \frac{(2x - 3)}{3} = 0 \\ \\ \frac{3 \times (3x + 5) - 4 \times (2x - 3)}{12} = 0 \\ \\ 3 \times (3x + 5) - 4 \times (2x - 3) = 0 \\ 9x + 15 - 8x + 12 = 0 \\ x + 27 = 0 \\ x = - 27[/tex]
Resposta:
[tex] \frac{(3x + 5)}{4} - \frac{(2x - 3)}{3} = 0 \\ \\ \frac{3 \times (3x + 5) - 4 \times (2x - 3)}{12} = 0 \\ \\ 3 \times (3x + 5) - 4 \times (2x - 3) = 0 \\ 9x + 15 - 8x + 12 = 0 \\ x + 27 = 0 \\ x = - 27[/tex]