Resposta:
[tex] \sqrt[7]{ {2}^{7} } = 2[/tex]
[tex]g) \sqrt[5]{32} = \sqrt[5]{ {2}^{5} } = 2[/tex]
[tex]h) \sqrt{ \frac{ {2}^{3} }{ {3}^{3} } } = \frac{2}{3} [/tex]
[tex]i) \frac{ \sqrt[3]{81} }{ \sqrt[3]{27} } = \frac{ \sqrt[3]{ {3}^{4} } }{ \sqrt[3]{ {3}^{3} } } = \frac{ \sqrt[3]{ {3}^{3}. {3}^{1} } }{3} = \frac{3 \sqrt{3} }{3} [/tex]
[tex]j) \frac{ \sqrt[4]{1296} }{ \sqrt[4]{2401} } = \frac{ \sqrt[4]{ {6}^{4} } }{ \sqrt[4]{ {7}^{4} } } = \frac{6}{7} [/tex]
[tex] \sqrt[7]{128} = \sqrt[7]{ {2}^{7} } = 2[/tex]
[tex]espero \: ter \: te \: ajudado[/tex]
