[tex]\Large\boxed{\begin{array}{l}\sf h(x)=4x^2+5\\\sf a=4>0\implies admite~m\acute inimo\\\sf\Delta=b^2-4ac\\\sf\Delta=0^2-4\cdot4\cdot5\\\sf\Delta=-80\\\sf y_V\longrightarrow altura~m\acute inima\\\sf y_V=-\dfrac{\Delta}{4a}\\\\\sf y_V=-\dfrac{-80}{4\cdot4}\\\\\sf y_V=\dfrac{80}{16}\\\\\sf y_V=5~m\end{array}}[/tex]
