Resposta :
[tex]\boxed{\begin{array}{l}\sf b=\sqrt{12}=\sqrt{2^2\cdot3}=2\sqrt{3}\\\sf a=\sqrt{2}\\\sf a\cdot b=\sqrt{2}\cdot2\sqrt{3}\\\sf a\cdot b=2\sqrt{6}\end{array}}[/tex]
[tex]\boxed{\begin{array}{l}\sf b=\sqrt{12}=\sqrt{2^2\cdot3}=2\sqrt{3}\\\sf a=\sqrt{2}\\\sf a\cdot b=\sqrt{2}\cdot2\sqrt{3}\\\sf a\cdot b=2\sqrt{6}\end{array}}[/tex]