Resposta:
a) -1 e -2
Explicação passo a passo:
Utilizamos a fórmula de Bháskara:
[tex]x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\\x = \frac{-3\pm \sqrt{3^2 - 4(1)(2)}}{2(1)}\\x= \frac{-3\pm \sqrt{9 - 8}}{2}\\x = \frac{-3 \pm \sqrt{1}}{2}\\x = \frac{-3\pm1}{2}\\x' = \frac{-3+1}{2}\\x' = \frac{-2}{2}\\x' = -1\\x'' = \frac{-3-1}{2}\\x''= \frac{-4}{2}\\x''=-2\\S=\{-2,-1\}[/tex]
