Se dois angulos opostos pelo vértice medem 3x - 10° e 6x - 46°, então a medida de x é:
A) 30°
B) 10°
C) 20°
D) 12°

[tex]\mathtt{3x - 10^{\circ} = 6x - 46^{\circ}} \\ \\ \mathtt{3x - 6x = - 46^{\circ} +10^{\circ} } \\ \\ \mathtt{ - 3x = - 46^{\circ} + 10^{\circ} } \\ \\ \mathtt{ - 3x = - 36^{\circ}} \\ \\ \mathtt{x = \frac{ - 36^{\circ}}{ - 3} } \\ \\ \red{\boxed{\boxed{\mathtt{x = 12^{\circ}}}}}[/tex]

Resposta: item (D).

Att: José Armando

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SOLKARPEDGO SOLKARPEDGO · Answer 2

✅ Após ter resolvido os cálculos, concluímos que o valor de "x" é:

[tex]\large\displaystyle\text{$\begin{gathered}\boxed{\boxed{\:\:\:\bf x = 12^{\circ}\:\:\:}} \end{gathered}$}[/tex]

Dois ângulos opostos pelo vértice possuem mesma medida.

Então:

[tex]\large\displaystyle\text{$\begin{gathered}3x - 10 = 6x - 46 \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}3x - 6x = -46 + 10 \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}-3x = -36 \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}3x = 36 \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}x = \frac{36}{3} \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}x = 12 \end{gathered}$}[/tex]

✅ Portanto, o valor de "x" é:

[tex]\large\displaystyle\text{$\begin{gathered}x = 12^{\circ} \end{gathered}$}[/tex]

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