Resposta :
[tex]sin(30\textdegree) = \frac{B}{30} \\\frac{1}{2} = \frac{B}{30}\\2*B = 30*1\\B = 15[/tex]
[B = 15 cm]
[tex]cos(30\textdegree) = \frac{C}{30}\\\frac{\sqrt{3} }{2} = \frac{C}{30}\\2*C = 30*\sqrt{3}\\C = 15\sqrt{3}[/tex]
[C ≅ 25.98 cm]
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[tex]sin(30\textdegree) = \frac{B}{30} \\\frac{1}{2} = \frac{B}{30}\\2*B = 30*1\\B = 15[/tex]
[B = 15 cm]
[tex]cos(30\textdegree) = \frac{C}{30}\\\frac{\sqrt{3} }{2} = \frac{C}{30}\\2*C = 30*\sqrt{3}\\C = 15\sqrt{3}[/tex]
[C ≅ 25.98 cm]