Resposta :
[tex] = ( \frac{1}{2} ) {}^{ - 2} + ( \frac{1}{3} ) {}^{ - 1} \\ \boxed{( \frac{1}{a} ) {}^{ - n} = a {}^{n} } \\ = 2 {}^{2} + 3 \\ = 4 + 3 \\ \boxed{ = 7}[/tex]
Att. NLE Top Shotta
[tex] = ( \frac{1}{2} ) {}^{ - 2} + ( \frac{1}{3} ) {}^{ - 1} \\ \boxed{( \frac{1}{a} ) {}^{ - n} = a {}^{n} } \\ = 2 {}^{2} + 3 \\ = 4 + 3 \\ \boxed{ = 7}[/tex]
Att. NLE Top Shotta