Resposta:
Explicação passo a passo:
1)
[tex]f'(x)=\frac{(cos(x)'.sen(x)-(sen(x))'.cos(x)}{sen^{2}x }\\\\f'(x)=\frac{-sen^{2}x-cos^{2}x }{sen^{2}x }\\\\f'(x)=\frac{(sen^{2}x+cos^{2}x) }{sen^{2}x }\\\\f'(x)=\frac{1}{sen^{2}x }=-cossec^{2}x\\\\f'(x)=-cossec^{2}x[/tex]
2) f(x) = x² +2x + 1
f'(x) = 2x + 2
