Resposta :
Explicação passo-a-passo:
a) (a+B)(a+c)=(a+b)a+(a+b)c=aa+ba+ac+bc
=a+ab+ac+bc=a(1+b+c)+bc=a+bc
b)a(-b)(-c)+a(-b)c+abc=a(bc+(-b)c+bc)=a(bc+(-b)c)=
Explicação passo-a-passo:
a) (a+B)(a+c)=(a+b)a+(a+b)c=aa+ba+ac+bc
=a+ab+ac+bc=a(1+b+c)+bc=a+bc
b)a(-b)(-c)+a(-b)c+abc=a(bc+(-b)c+bc)=a(bc+(-b)c)=