Explicação passo-a-passo:
[tex] \frac{2}{ \sqrt{10} } . \frac{ \sqrt{10} }{10} = \frac{2 \sqrt{10} }{ \sqrt{100} } = \frac{2 \sqrt{10} }{10} = \frac{ \sqrt[]{10} }{5} \\ d) \frac{20}{ \sqrt{2} }. \frac{ \sqrt{2} }{ \sqrt{2} } = \frac{20 \sqrt{2} }{ \sqrt{4} } = \frac{20 \sqrt{2} }{2} = 10 \sqrt{2} \\ e) \frac{21}{ \sqrt{3} }. \frac{ \sqrt{3} }{ \sqrt{3} } = \frac{21 \sqrt{3} }{ \sqrt{9} } = \frac{21 \sqrt{3} }{3} = 7 \sqrt{3} \\ f) \frac{ \sqrt{5} }{ \sqrt{2} }. \frac{ \sqrt{2} }{ \sqrt{2} } = \frac{ \sqrt{10} }{ \sqrt{4} } = \frac{ \sqrt{10} }{2} \\ g) \frac{ \sqrt{7} }{ \sqrt{5} }. \frac{ \sqrt{5} }{ \sqrt{5} } = \frac{ \sqrt{35} }{ \sqrt{25} } = \frac{ \sqrt{35} }{5} \\ h) \frac{ \sqrt{3} }{ \sqrt{11} }. \frac{ \sqrt{11} }{ \sqrt{11} } = \frac{ \sqrt[2]{33} }{ \sqrt{121} } = \frac{ \sqrt{33} }{11} \\ i) \frac{6}{ \sqrt{6} }. \frac{ \sqrt{6} }{ \sqrt{6} } = \frac{6 \sqrt{6} }{ \sqrt{36} } = \frac{6 \sqrt{6} }{6} = \sqrt{6} [/tex]
