Resposta:
[tex]\left(2\sqrt{x+1}+3\sqrt{x-4}\right)\\\\\left(2\sqrt{x+1}\right)+\left(3\sqrt{x-4}\right)\\\\\left(2\sqrt{x+1}\right)=\frac{1}{\sqrt{x+1}}\\\\\left(3\sqrt{x-4}\right)=\frac{3}{2\sqrt{x-4}}\\\\=\frac{1}{\sqrt{x+1}}+\frac{3}{2\sqrt{x-4}}[/tex]
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[tex]x^-^2+x^-^1+8\\\\\frac{1}{x^2}+x^{-1}+8\\\\\frac{1}{x^2}+\frac{1}{x}+8[/tex]
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[tex]\frac{2}{x^3}+\frac{1}{x^2}+\frac{3}{x}\\\\\frac{2}{x^3}+\frac{x}{x^3}+\frac{3x^2}{x^3}\\\\\frac{2+x+3x^2}{x^3}[/tex]
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[tex]m^\frac{4}{3} +m^5\\\\\frac{3m}{4}+m^5[/tex]
