Resposta:
a)
[tex] {x}^{2} + 12x - 13 + 49 =0 + 49 \\ {x}^{2} + 12x + 36 = 49 \\ {(x + 6)}^{2} = 49 \\ x + 6 = \sqrt{49} \\ x1 = + 7 - 6 = 1 \\ x2 = - 7 - 6 = 13[/tex]
b)
[tex] { x}^{2} + 6x + 8 + 1 = 0 + 1 \\ {x}^{2} + 6x + 9 = 1 \\ {(x + 3)}^{2} = 1 \\ x + 3 = \sqrt{1} \\ x1 =1 - 3 = - 2 \\ x2 = - 1 - 3 = - 4[/tex]
