Resposta:
x+3
=x−3(
x+3
)
2
=(x−3)
2
x+3=x
2
−6x+9−x
2
+6x−9+x+3=0−x
2
+7x−6=0
Δ = b² - 4ac
Δ = 7² - 4(-1)(-6)
Δ = 49 - 24
Δ = 25
x' = (-b + √Δ)/2a x'' = (-b - √Δ)/2a
x' = (-7 + √25)/2(-1) x'' = (-7 - √25)/2(-1)
x' = (-7 + 5)/-2 x'' = (-7 - 5)/-2
x' = -2/-2 x'' = -12/-2
x' = 1 x'' = 6
S = {1, 6}
