se poder simplificar agradeço
gente pfv me ajudem​


Se Poder Simplificar Agradeçogente Pfv Me Ajudem class=

Resposta :

[tex]a)\\\frac{1}{3}+\frac{5}{2}\\\\=\frac{2}{6}+\frac{15}{6}\\\\=\frac{2+15}{6}\\\\\mathrm{Somar:}\:2+15=17\\\\=\frac{17}{6}[/tex]

[tex]b)\\\frac{4}{7}-\frac{8}{10}\\\\=\frac{4}{7}-\frac{4}{5}\\\\=\frac{20}{35}-\frac{28}{35}\\\\\mathrm{Somar:}\:20-28=-8\\\\=\frac{-8}{35}\\\\\mathrm{Aplicar\:as\:propriedades\:das\:fracoes}:\\\\=-\frac{8}{35}[/tex]

[tex]c)\\\frac{2}{5}+\frac{3}{6}\\\\=\frac{2}{5}+\frac{1}{2}\\\\=\frac{4}{10}+\frac{5}{10}\\\\=\frac{4+5}{10}\\\\\mathrm{Somar:}\:4+5=9\\\\=\frac{9}{10}[/tex]

[tex]d)\\\frac{6}{7}-\frac{9}{7}\\\\\frac{6-9}{7}\\\\\mathrm{Somar:}\:6-9=-3\\\\=\frac{-3}{7}\\\\=-\frac{3}{7}[/tex]

[tex]e)\\\frac{3}{10}+\frac{4}{2}\\\\=\frac{3}{10}+\frac{20}{10}\\\\\mathrm{Somar:}\:3+20=23\\\\=\frac{23}{10}[/tex]

[tex]f)\\\frac{4}{9}-\frac{8}{6}\\\\=\frac{4}{9}-\frac{12}{9}\\\\=\frac{4-12}{9}\\\\\mathrm{Somar:}\:4-12=-8\\\\=\frac{-8}{9}\\\\=-\frac{8}{9}[/tex]

a) 1/3 + 5/2

mmc

3 , 2 2

3 , 1 3

1 , 1 / 3 . 2 = 6

2.1/6 + 3.5/6

2/6 + 15/6

17/6

b) 4/7 - 8/10

mmc

7 , 10 2

7 , 5 5

7 , 1 7

1 , 1 / 2 . 5 . 7 = 70

10.4/70 - 7.8/70

40/70 - 56/70

-16/70 = -8/35

c) 2/5 + 3/6

mmc

5 , 6 2

5 , 3 3

5 , 1 5

1 , 1 / 2 . 3 . 5 = 30

6.2/30 + 5.3/30

12/30 + 15/30

27/30 = 9/10

d) 6/7 - 9/7 = -3/7

e) 3/10 + 4/2

mmc

10 , 2 2

5 , 1 5

1 , 1 / 5 . 2 = 10

3/10 + 5.4/10

3/10 + 20/10 = 23/10

f) 4/9 - 8/6

mmc

9 , 6 2

9 , 3 3

3 , 1 3

1 , 1 / 2 . 3 . 3 = 18

2.4/18 - 3.8/18

8/18 - 24/18

-16/18 = -8/9