Resposta:
a) sen 8400
8400/360= 23,3333...
pegue a parte inteira=23
8400-23*360=120
sen(120)=sen(60+60)=2*sen(60)*cos(60)=2*(√3/2)*(1/2)
sen(8400)=sen(120)=√3/2
b) cos 23100
23100/360=64,1666...
23100-64*360=60
sen(23100)=sen(60)=√3/2
c) tg 41*pi/4 = tg 41*180/4 =tg 1845
1845/360=5,125
1845-5*360 = 45
tg 41*pi/4 =tg 45= 1
