Resposta:
[tex]a) {n}^{2} = ( {n}^{2} )^{3} = n ^{2 \times 3} = {n}^{6} [/tex]
[tex]b) - n^{2} = ( { - n}^{2} )^{3} = - n ^{2 \times 3} = { - n}^{6} [/tex]
[tex]c) - 3a {b}^{2} = ( - 3a {b}^{2} ) ^{3} = [/tex]
[tex] = {( - 3)}^{3} \times {a}^{3} \times {b}^{2 \times 3} = - 27 {a}^{3} {b}^{6} [/tex]
[tex]d) \frac{1}{4} abc = ( \frac{1}{4} abc) ^{3} = \frac{1}{64} {a}^{3} {b}^{3} {c}^{3} [/tex]
Espero ter ajudado.
