Resposta:
[tex]a)\sqrt{8} \ . \ \sqrt{6} \\\\\ \sqrt{8} =2 \sqrt{2} \\\2\sqrt{2} \ . \ \sqrt{6} \\\\2\sqrt{2} \ . \ \ 2 \sqrt{2 \ . \ 3} \\\\2 \ . \ 2\sqrt{3} \\\\4\sqrt{3}[/tex]
[tex]b)\sqrt{2} \ . \ \sqrt{27} \\\\\sqrt{27} =3\sqrt{3} \\\\2 \ . \ 3\sqrt{3} \\\\3\sqrt{2 \ . \ 3} \\\\3\sqrt{6}[/tex]
[tex]c)\sqrt{42} \ . \ \sqrt{28} \\\\\sqrt{28} =2\sqrt{7} \\\\\sqrt{42} \ . \ 2\sqrt{7} \\\\\sqrt{7} \sqrt{6} \ . \ 2\sqrt{7} \\\\2 \ . \ 7\sqrt{6} \\\\14\sqrt{6}[/tex]
Explicação passo-a-passo:
[tex]espero \ ter \ ajudo![/tex]
[tex]bom \ fim\ de \ semana \ amigo(a)![/tex]
