Resposta:
Explicação passo-a-passo:
[tex]\frac{3}\sqrt{4} } +\frac{1}{\sqrt{16}+\sqrt4} } \\\\\frac{3}{2} +\frac{1}{4+2} \\\\\frac{3}{2} +\frac{1}6} \\\\=\frac{9+1}{6} \\\\=\frac{10}{6} sinplificando =\frac{5}{3}[/tex]
[tex]\sqrt{\sqrt[3]{8} -\sqrt{25}+\sqrt{\sqrt{625} } } \\\\\sqrt{\sqrt[3]{2^{3} }-5 +\sqrt{25} }\\\\\sqrt{2-5+5} \\\\\sqrt{2}[/tex]
