Explicação:
F=24N
m=m
v=12m/s
t=2s
Aplicação da lei de Newton:
F=m×a→ F=m×v∆/∆t
24=m×12/2
48/12=m
4kg=m
m=4kg
[tex]\large\boxed{\begin{array}{l}\sf A\,acelerac_{\!\!,}\tilde{a}o\,\acute{e}\,igual\,ao\,valor\,da\\\sf variac_{\!\!,}\tilde{a}o\,da\,velocidade\,dividido\,pelo\\\sf intervalo\,de\,tempo.\\\sf acelerac_{\!\!,}\tilde{a}o=\dfrac{variac_{\!\!,}\tilde{a}o\,da\, velocidade}{intervalo\,de\, tempo}\\\\\sf a=\dfrac{12\,\bigg[\dfrac{m}{s}\bigg]}{2\,[s]}\\\\\sf a=6\,\bigg[\dfrac{m}{s^2}\bigg]\end{array}}[/tex]
[tex]\large\boxed{\begin{array}{l}\sf Agora\, podemos\,aplicar\,a\, f\acute{o}rmula.\\\sf F=m\cdot a\iff m=\dfrac{F}{a}\\\sf m=\dfrac{24}{6}\\\\\sf m=4\,kg\end{array}}[/tex]
