✅ Após resolver os cálculos, concluímos que o polinômio "S(x)" que representa a soma dos polinômios "P(x)" e "Q(x)" é:
[tex]\Large\displaystyle\text{$\begin{gathered}\boxed{\boxed{\:\:\:\bf S(x) = 7x^{3} + 7x^{2} + 3x - 1\:\:\:}}\end{gathered}$}[/tex]
Sejam os polinômios:
[tex]\Large\begin{cases} P(x) = 7x^{3} + 12x^{2} - 4x + 3\\Q(x) = -5x^{2} + 7x - 4\\S(x) = \:?\end{cases}[/tex]
Calculando a soma "S(x)" dos referidos polinômios:
[tex]\Large\displaystyle\text{$\begin{gathered} S(x) = P(x) + Q(x)\end{gathered}$}[/tex]
[tex]\Large\displaystyle\text{$\begin{gathered} = (7x^{3} + 12x^{2} - 4x + 3) + (-5x^{2} + 7x - 4)\end{gathered}$}[/tex]
[tex]\Large\displaystyle\text{$\begin{gathered} = 7x^{3} + 12x^{2} - 4x + 3 - 5x^{2} + 7x - 4\end{gathered}$}[/tex]
[tex]\Large\displaystyle\text{$\begin{gathered} = 7x^{3} + 7x^{2} + 3x - 1\end{gathered}$}[/tex]
✅ Portanto, a soma dos polinômios é:
[tex]\Large\displaystyle\text{$\begin{gathered} S(x) = 7x^{3} + 7x^{2} + 3x - 1\end{gathered}$}[/tex]
[tex]\LARGE\displaystyle\text{$\begin{gathered} \underline{\boxed{\boldsymbol{\:\:\:Bons \:estudos!!\:\:\:Boa\: sorte!!\:\:\:}}}\end{gathered}$}[/tex]
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