Resposta :
[tex]( \frac{1}{3} - x)^{2} = \\ \\ { \frac{1}{3} }^{2} - 2. \frac{1}{3} .x + {x}^{2} = \\ \\ \frac{1}{9} - \frac{2x}{3} + {x}^{2} [/tex]
[tex]( \frac{1}{3} - x)^{2} = \\ \\ { \frac{1}{3} }^{2} - 2. \frac{1}{3} .x + {x}^{2} = \\ \\ \frac{1}{9} - \frac{2x}{3} + {x}^{2} [/tex]