[tex]\boxed{\begin{array}{l}\sf\sqrt[\sf5]{\sf3^2}\cdot\sqrt[\sf5]{\sf3^3}=\sqrt[\sf5]{\sf3^2\cdot3^3}\\\sf\sqrt[\sf5]{\sf3^{3+2}} =\sqrt[\sf\diagup\!\!\!5]{\sf3^{\diagup\!\!\!5}}=3\\\huge\boxed{\boxed{\boxed{\boxed{\sf\maltese~alternativa~D}}}}\end{array}}[/tex]
