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[tex]\large\boxed{\begin{array}{l}\sf tg(60^\circ)=\dfrac{AM}{BM}\\\sf\diagdown\!\!\!\!\!\!\sqrt{3}=\dfrac{4\diagdown\!\!\!\!\!\!\sqrt{3}}{BM}\\\sf BM=4~dm\\\sf BC=BM+MC\\\sf BC=4+13=17~dm\\\sf A=\dfrac{(BC+AD)\cdot AM}{2}\\\sf A=\dfrac{(17+13)\cdot\diagdown\!\!\!\!4\sqrt{3}}{\diagdown\!\!\!2}\\\sf A=30\cdot2\sqrt{3}\\\sf A=60\sqrt{3}~dm^2\end{array}}[/tex]
