Força elétrica :
[tex]\displaystyle \text{F}_\text e =\frac{\text{k}.|\text q_1|.|\text q_2|}{\text d^2}[/tex]
Temos :
[tex]\text F_\text e =3,6\ \text N \\\\ \text k = 9.10^9 \\\\ \text q_1=\text q_2=\text q \\\\ \text d = 10 \ \text{cm} =10.10^{-2} \ \text m[/tex]
substituindo na fórmula :
[tex]\displaystyle 3,6=\frac{9.10^9.\text q.\text q}{(10.10^{-2})^2} \\\\\\ 36.10^{-1} = \frac{9.10^{9}.\text q^2}{10^{-2}} \\\\\\ \text q^2 = \frac{36.10^{-1}.10^{-2}}{9.10^{9}} \\\\\\ \text q ^2 =4.10^{-12} \\\\ \text q = \sqrt{4.10^{-12}} \\\\\ \huge\boxed{\text q = 2.10^{-6}\ \text C\ }\checkmark[/tex]
letra A
