Resposta :
[tex]\mathbf{Dados}\Longrightarrow m=4.2\ \text{kg}=4200\ \text{g};\\ \Delta\theta=280-40=240\mathrm{^{\circ}C};\ c=0.23\ \mathrm{cal/g^{\circ}C}.[/tex]
[tex]\boxed{Q=cm\Delta\theta}\Longrightarrow Q=(0.23)(4200)(240)[/tex]
[tex]\Longrightarrow Q=231840\ \text{cal}\ \therefore\ \boxed{Q=231.84\ \mathrm{kcal}}[/tex]