Resposta :
[tex]\boxed{(x-x_C)^2+(y-y_C)^2=r^2}[/tex]
[tex]C(x_C,y_C)=C(0,0)\\ r=1\ u.c.[/tex]
[tex](x-0)^2+(y-0)^2=1^2\ \therefore[/tex]
[tex]\boxed{x^2+y^2=1}[/tex]
[tex]\boxed{(x-x_C)^2+(y-y_C)^2=r^2}[/tex]
[tex]C(x_C,y_C)=C(0,0)\\ r=1\ u.c.[/tex]
[tex](x-0)^2+(y-0)^2=1^2\ \therefore[/tex]
[tex]\boxed{x^2+y^2=1}[/tex]