Resposta :
- Faz uma equação de 1° grau
[tex]\sf 15\cdot \:y\:-\:6\:=\:12\cdot \:y\:+\:60\:\\\\\\\sf 15y-6+6=12y+60+6\\\\\\\sf 15y=12y+66\\\\\\\sf 15y-12y=12y+66-12y\\\\\\\sf 3y=66\\\\\\\sf \dfrac{3y}{3}=\dfrac{66}{3}\\\\\\\boxed{\sf S=\{22 \}}[/tex]
⋅y−6=12⋅y+60
15y−6+6=12y+60+6
15y=12y+66
15y−12y=12y+66−12y
3y=66
3
3y
=
3
66
S={22}