Resposta :
c) a + b
[tex]\frac{1}{3} + (-\frac{1}{5} ) = \frac{1}{3} -\frac{1}{5} = \frac{5-3}{15} = \frac{2}{15}[/tex]
d) √b² - 4 . a .c =
√(-3)² - 4 . 1 . 2 =
√9 - 8 =
√1 = 1
c) a + b
[tex]\frac{1}{3} + (-\frac{1}{5} ) = \frac{1}{3} -\frac{1}{5} = \frac{5-3}{15} = \frac{2}{15}[/tex]
d) √b² - 4 . a .c =
√(-3)² - 4 . 1 . 2 =
√9 - 8 =
√1 = 1