Resposta :
→ Cálculo :
[tex]\large { \ {\boxed { \begin{array}{lr} {15+[(3\times6-2)-(6\div2)]} \\ \\ {15+[(18-2)-3]}\\\\{15+[16-3]}\\\\{15+13}\\\\\boxed{\red{ \: \: 28 \: \: }} \rm \ {\blue \Leftrightarrow} \ \pink R \pink e \pink \pink \pink s \pink p \pink o \pink s \pink t \pink a \\ \end{array}}}}[/tex]