[tex]\displaystyle \text{Tg}(60^{\circ})=\frac{\text H }{10 }[/tex]
[tex]\displaystyle \sqrt{3} = \frac{\text H }{10}[/tex]
Portanto :
[tex]\huge\boxed{\displaystyle \text H = 10\sqrt{3} \ \text m }\checkmark[/tex]
