Resposta :
[tex] \sqrt{ {2}^{8} } = {2}^{ \frac{8}{12 } ^{ \div 2} } = {2}^{ \frac{4}{6} ^{ \div 2} } = {2}^{ \frac{2}{3} } [/tex]
[tex] \sqrt{ {2}^{8} } = {2}^{ \frac{8}{12 } ^{ \div 2} } = {2}^{ \frac{4}{6} ^{ \div 2} } = {2}^{ \frac{2}{3} } [/tex]