Respondido

Efetue as operações com angulos:

A) 67°30'+22°30'

B) 52°17'50''-41°5'18''

C) (12°19'15'').4

D) (84°40'20''):2

Resposta :

CRUZEIRISTAGO

Resposta:

A) 67°30'+22°30' = (67° + 22°) + (30' + 30') = 89° 60' = 90°00'

B) 52°17'50''-41°5'18'' = 11°'12''32

C) (12°19'15'').4 = 48°76'60'' = 48°77'00'' = 49°17'00''

D) (84°40'20''):2 = 42°20'10''

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