Resposta:
[tex]b)-\frac{1}{32} c)\frac{1}{36} d)\frac{10}{3}[/tex]
Explicação passo-a-passo:
[tex]a^{-1}=\frac{1}{a}\\\\b)(-2)^{-5} = -\frac{1}{2}^5=-\frac{1}{32} \\\\c)6^{-2}=\frac{1}{6}^{2} = \frac{1}{36}\\\\d)0,3 = \frac{3}{10}^{-1}=\frac{10}{3}[/tex]
